閱讀下面問題:
11+√2=1×(√2-1)(√2+1)(√2-1)=√2-1;
1√3+√2=√3-√2(√3+√2)(√3-√2)=√3-√2;
1√5+2=√5-2(√5+2)(√5-2)=√5-2.
試求:(1)1√7+√6的值;
(2)1√n+1+√n(n為正整數(shù))的值.
(3)計(jì)算:11+√2+1√2+√3+1√3+√4+…+1√98+√99+1√99+√100.
1
1
+
√
2
=
1
×
(
√
2
-
1
)
(
√
2
+
1
)
(
√
2
-
1
)
=
√
2
-
1
1
√
3
+
√
2
=
√
3
-
√
2
(
√
3
+
√
2
)
(
√
3
-
√
2
)
=
√
3
-
√
2
1
√
5
+
2
=
√
5
-
2
(
√
5
+
2
)
(
√
5
-
2
)
=
√
5
-
2
1
√
7
+
√
6
1
√
n
+
1
+
√
n
1
1
+
√
2
+
1
√
2
+
√
3
+
1
√
3
+
√
4
+
…
+
1
√
98
+
√
99
+
1
√
99
+
√
100
【考點(diǎn)】分母有理化.
【答案】見試題解答內(nèi)容
【解答】
【點(diǎn)評(píng)】
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發(fā)布:2024/4/20 14:35:0組卷:3184引用:63難度:0.3
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