間氨基苯乙炔(K)是新型抗腫瘤藥物鹽酸厄洛替尼的關鍵中間體。用苯為原料的合成路線之一如圖所示:
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(1)化合物B的化學名稱為 硝基苯硝基苯;化合物C的結構簡式為 
。
(2)D→E的反應類型為 加成反應加成反應,化合物K中所含官能團名稱為 氨基、碳碳三鍵氨基、碳碳三鍵。
(3)F→G反應的化學方程式為
濃硫酸△
+H2O
濃硫酸△
+H2O(注明反應的具體條件)。
(4)G的同分異構體中,滿足下列條件的同分異構體有 1111種。
①與G含有相同的官能團
②屬于二取代芳香族化合物
寫出其中核磁共振氫譜有4種峰,其峰值面積比為1:2:2:2的所有結構簡式:
和
和
。
(5)設計由
、乙醛、無水乙醚和本題合成路線中的無機試劑制備
的合成路線:(合成需要四步) 
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濃H2SO4△
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濃H2SO4△
。
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濃硫酸
△
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濃硫酸
△
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濃
H
2
S
O
4
△
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濃
H
2
S
O
4
△
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【考點】有機物的合成.
【答案】硝基苯;
;加成反應;氨基、碳碳三鍵;
+H2O;11;
和
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濃硫酸
△
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濃
H
2
S
O
4
△
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【解答】
【點評】
聲明:本試題解析著作權屬菁優(yōu)網所有,未經書面同意,不得復制發(fā)布。
發(fā)布:2024/9/6 1:0:8組卷:1引用:2難度:0.5
相似題
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1.由物質a為原料,制備物質d (金剛烷)的合成路線如圖所示:
關于以上有機物的說法中,不正確的是( ?。?/h2>發(fā)布:2024/12/30 14:30:1組卷:18引用:2難度:0.7 -
2.油脂不僅是營養(yǎng)物質和主要食物,也是一種重要的工業(yè)原料。如圖是以油脂為主要原料獲得部分產品的合成路線:
已知:
①
②(R1、R2、R3與R4可能是氫、烴基或其他基團)
回答下列問題:
(1)下列關于油脂的說法正確的是
a.油脂包括植物油和脂肪,屬于酯類
b.天然油脂是混合物,無固定的熔點和沸點
c.油脂屬天然高分子化合物
d.硬化油又叫人造脂肪,便于儲存和運輸,但容易被空氣氧化變質
(2)G中官能團的名稱為
(3)用系統(tǒng)命名法寫出A的名稱
(4)二元取代芳香化合物H是G的同分異構體,H滿足下列條件:
①能發(fā)生銀鏡反應,②酸性條件下水解產物物質的最之比為2:1,③不與NaHCO3溶液反應。
則符合上述條件的H共有
(5)寫出從HOCH2CH2OH→HCOOCH2CH2OOCH 的合成路線(無機試劑任選,合成路線參照題中的書寫形式)發(fā)布:2025/1/9 8:0:2組卷:10引用:1難度:0.1 -
3.有機物K是某藥物的前體,合成路線如圖所示。
已知:R-CNR-CH2NH2;H2催化劑
R1-NH2+R2-COOC2H5催化劑+C2H5OH。
(1)B的結構簡式是
(2)反應③的化學方程式是
(3)E屬于烴,其分子式是
(4)H中含氧官能團的名稱是
(5)寫出滿足下列條件的K的一種同分異構體的結構簡式:
①遇氯化鐵溶液顯紫色;
②不含醚鍵;
③核磁共振氫譜顯示峰面積之比為2:12:2:2:1。
(6)H經三步反應合成K,寫出J→K的化學方程式發(fā)布:2024/12/30 11:0:1組卷:11引用:3難度:0.3